4x−2\frac{4}{x-2}x−24 - x2x(x−2)\frac{x}{2x(x-2)}2x(x−2)x
asked by guest on Apr 04, 2025 at 6:36 pm
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MathBot Answer:
4x−2−x2x(x−2)=72(x−2)\displaystyle \frac{4}{x - 2} - \frac{x}{2 x \left(x - 2\right)} = \frac{7}{2 \left(x - 2\right)} x−24−2x(x−2)x=2(x−2)7
4x−2−x2x(x−2)=−x2x2−4x+4x−2\frac{4}{x - 2} - \frac{x}{2 x \left(x - 2\right)} = - \frac{x}{2 x^{2} - 4 x} + \frac{4}{x - 2}x−24−2x(x−2)x=−2x2−4xx+x−24