if 2^x=2025 and 45^y=8, what is xy

asked by guest
on Mar 29, 2025 at 6:47 am



MathBot Answer:

The system of equations has one solution.

x=2log⁡(45)log⁡(2),y=3log⁡(2)log⁡(45)x = \frac{2 \log{\left(45 \right)}}{\log{\left(2 \right)}}, y = \frac{3 \log{\left(2 \right)}}{\log{\left(45 \right)}}

By substituting these values into the expression, we find that: xy=6\begin{aligned}x y &= 6\end{aligned}

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