a^2x × a^y=a^3 , (a^3)^x ÷ a^4y=a^32

asked by guest
on Jan 28, 2025 at 5:22 pm



You asked:

Solve the system of equations:a2xay=a3a3xa4y=a32\begin{aligned}{a}^{2} x {a}^{y} &= {a}^{3}\\\frac{{{a}^{3}}^{x}}{{a}^{4} y} &= {a}^{32}\end{aligned}