asked by guest
on Mar 16, 2025 at 7:07 pm
You asked:
Investigate the equation:
y=21(x+1)2−3.
MathBot Answer:
The graph of the equation y=21(x+1)2−3 is a parabola.
The coordinates of its vertex are: (−1,−3)
The coordinates of its focus are: (−1,−25)
The directrix has equation: 2y+7=0.
The parabola has parameterization: x(θ)y(θ)=−1+θ=−3+2θ2