x{3(x-1)(x-2)+2[x(x+7)]}
You asked:
Evaluate the expression: \(x \cdot \left(3 \cdot \left(x - 1\right) \cdot \left(x - 2\right) + 2 \cdot x \cdot \left(x + 7\right)\right)\)
MathBot Answer:
Evaluated
\(\displaystyle x \cdot \left(3 \cdot \left(x - 1\right) \cdot \left(x - 2\right) + 2 \cdot x \cdot \left(x + 7\right)\right) = x \left(2 x \left(x + 7\right) + 3 \left(x - 2\right) \left(x - 1\right)\right) \)
Expanded
\[x \cdot \left(3 \cdot \left(x - 1\right) \cdot \left(x - 2\right) + 2 \cdot x \cdot \left(x + 7\right)\right) = 5 x^{3} + 5 x^{2} + 6 x\]
Factored
\[x \cdot \left(3 \cdot \left(x - 1\right) \cdot \left(x - 2\right) + 2 \cdot x \cdot \left(x + 7\right)\right) = x \left(5 x^{2} + 5 x + 6\right)\]