ln(2)/(2.288*10^9)=g
You asked:
Solve the equation \(\frac{\ln\left( 2 \right)}{2.288 \cdot {10}^{9}} = g\) for the variable \(g\).
MathBot Answer:
The solution is: \[g = \frac{\log{\left(2 \right)}}{2288000000} \approx 3.0294894 \cdot 10^{-10}\]
\[\begin{aligned}\frac{\log{\left(2 \right)}}{2288000000} &= g\\- g &= - \frac{\log{\left(2 \right)}}{2288000000}\\g &= \frac{\log{\left(2 \right)}}{2288000000}\end{aligned}\]