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x^2+y^2+4x+6y+16=0
asked by
guest
on Nov 15, 2024 at 2:24 am
You asked:
Investigate the equation:
x
2
+
y
2
+
4
x
+
6
y
+
16
=
0
{x}^{2} + {y}^{2} + 4 x + 6 y + 16 = 0
x
2
+
y
2
+
4
x
+
6
y
+
16
=
0
.
MathBot Answer:
You entered an equation of an imaginary circle centered at
(
x
,
y
)
=
(
−
2
,
−
3
)
\left(x, y\right) = \left(-2, -3\right)
(
x
,
y
)
=
(
−
2
,
−
3
)
with radius
3
i
\sqrt{3} i
3
i
.
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