x^2+y^2+4x+6y+16=0

asked by guest
on Nov 15, 2024 at 2:24 am



You asked:

Investigate the equation: \({x}^{2} + {y}^{2} + 4 x + 6 y + 16 = 0\).

MathBot Answer:

You entered an equation of an imaginary circle centered at \(\left(x, y\right) = \left(-2, -3\right)\) with radius \(\sqrt{3} i\).

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