(0.50*(1.91-0.0367)^2 )+(0.24*(1.88-0.0367)^2 )+(0.059*(1.61-0.0367)^2 )+(0.076*(1.66-0.0367)^2 )+(0.082*(1.83-0.0367)^2 )+(0.026*(1.54-0.0367)^2 )+(0.017*(2.16-0.0367)^2)

asked by guest
on Apr 26, 2025 at 5:27 am



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