|z-3|^2 + 1/2 < 1

asked by guest
on Nov 25, 2024 at 12:28 pm



You asked:

Solve the inequality \( {\left\lvert z - 3\right\rvert}^{2} + \frac{1}{2} < 1 \) for the variable \(z\).

MathBot Answer:

\[3 - \frac{\sqrt{2}}{2} \lt z \lt \frac{\sqrt{2}}{2} + 3\]