Consider a circle M of radius ((al) and a circle N of radius \(bl), where \(\dfrac(a2) < b < al). The center of circle M lies on a point on the circumference of circle N. A triangle is formed with its vertices as the center of circle M and the two points of intersection between circle M and circle N. The area of the triangle is given by (\dfrac(49\sqrt{51)X207). Find the area of circle M.

asked by guest
on Nov 23, 2024 at 5:23 pm



Mathbot Says...

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