(1+x²+y²+x²y²)½+xydy/dx=0 solve the differential equation

asked by guest
on Nov 16, 2024 at 5:45 am



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Investigate the equation: (1+x2+y2+x2y2)⋅12+xydydx=0\left(1 + {x}^{2} + {y}^{2} + {x}^{2} {y}^{2}\right) \cdot \frac{1}{2} + \frac{x y d y}{d x} = 0.

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