∑i=16−4\sum_{i=1}^{6}{-4}i=1∑6−4
asked by guest on Mar 28, 2025 at 12:01 pm
You asked:
MathBot Answer:
∑i=16−4=−24\sum_{i=1}^{6} -4 = -24i=1∑6−4=−24
∑i=16−4=(−4)6 by the identity∑n=1mC=mC=−24\begin{aligned}\sum_{i=1}^{6} -4 &= \left(-4\right) 6 \ \ \ \small{\color{grey}\text{by the identity} \sum_{n=1}^{m} C = mC}\\&= -24\end{aligned}i=1∑6−4=(−4)6 by the identityn=1∑mC=mC=−24