9^2x = 1/3(27^x)

asked by guest
on Sep 25, 2024 at 1:23 pm



You asked:

Solve the equation \({9}^{2} \cdot x = \frac{1}{3 \cdot {27}^{x}}\) for the variable \(x\).

MathBot Answer:

The solution is: \[x = \frac{0.0133828112457117860635866031883255440646450274124}{\log{\left(27 \right)}} \approx 0.0040605199\]

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