(-8, 9) and (1, -9)
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MathBot Answer:
Standard Form:
\[ \begin{aligned}Ax + By + C = 0\end{aligned} \] \[ \begin{aligned} \text{Slope} &= -\frac{A}{B} \\ &= \frac{y_2-y_1}{x_2-x_1} \\ -\frac{A}{B} &= \frac{ -9 - 9 }{ 1 - -8 } \\ -\frac{A}{B} &= \frac{ -18 }{ 9 } \\ A =& 18, B = 9 \end{aligned} \] \[ \begin{aligned} 18 x + 9 y + C &= 0 \\ 18(-8) + 9(9) + C &= 0 \\ + + C &= 0 \\ 81 + C &= 144 \\ C &= -63 \end{aligned} \] An equation of the line in standard form is: \[ 18 x + 9 y + 63 = 0 \]
Slope-Intercept Form:
\[ y = m x + b \] \[ \begin{aligned} \text{Slope} &= \frac{y_2-y_1}{x_2-x_1} \\ \text{Slope} &= \frac{ -9 - 9 }{ 1 - -8 } \\ \text{Slope} &= -2 \end{aligned} \] \[ \begin{aligned} y &= -2 x + b \\ 9 &= -2 \times -8 + b \\ 9 &= 16 + b \\ b &= -7 \end{aligned} \] The slope-intercept form of the line is: \[ y = - 2 x - 7 \]