Math Problem Solver

\[ \frac{1}{2} + \frac{6}{8} + \frac{3}{4} = 2 \]

The sum can be computed by rewriting each term over a common denominator, where the least common denominator of \(\frac{1}{2}\), \(\frac{6}{8}\), and \(\frac{3}{4}\) is \(8\). \[ \begin{aligned} \frac{1}{2} + \frac{6}{8} + \frac{3}{4} &= \frac{1 \cdot 4}{2 \cdot 4} + \frac{6 \cdot 1}{8 \cdot 1} + \frac{3 \cdot 2}{4 \cdot 2} \\ &= \frac{4 + 6 + 6}{8} \\ &= \frac{16}{8} \\&= 2 \end{aligned} \]