(8x-y)(x+3y)-( 4x+y)(9y-2x)

asked by guest
on Apr 02, 2025 at 10:08 pm



You asked:

Evaluate the expression: (8x−y)(x+3y)−(4x+y)(9y−2x)\left(8 x - y\right) \left(x + 3 y\right) - \left(4 x + y\right) \left(9 y - 2 x\right)

MathBot Answer:

Evaluated



(8x−y)(x+3y)−(4x+y)(9y−2x)=−(−2x+9y)(4x+y)+(8x−y)(x+3y)\displaystyle \left(8 x - y\right) \left(x + 3 y\right) - \left(4 x + y\right) \left(9 y - 2 x\right) = - \left(- 2 x + 9 y\right) \left(4 x + y\right) + \left(8 x - y\right) \left(x + 3 y\right)

Expanded

(8x−y)(x+3y)−(4x+y)(9y−2x)=16x2−11xy−12y2\left(8 x - y\right) \left(x + 3 y\right) - \left(4 x + y\right) \left(9 y - 2 x\right) = 16 x^{2} - 11 x y - 12 y^{2}

Factored

(8x−y)(x+3y)−(4x+y)(9y−2x)=16x2−11xy−12y2\left(8 x - y\right) \left(x + 3 y\right) - \left(4 x + y\right) \left(9 y - 2 x\right) = 16 x^{2} - 11 x y - 12 y^{2}

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