(.1)(800)(x-25)=(.25)(4182)(x-80)

asked by guest
on Jan 21, 2025 at 4:21 am



You asked:

Solve the equation .1⋅800(x−25)=.25⋅4182(x−80).1 \cdot 800 \left(x - 25\right) = .25 \cdot 4182 \left(x - 80\right) for the variable xx.

MathBot Answer:

The solution is: x=1632801931=84.55722423614707405489383738995339202485758674262040393578456758156395649922320041429311237700673226307612635939927498705334023821853961677887105126877265665458311755567063697566027964785085447954427757638529259451061626100466079751424132573795960642154324184360435007767995857068876229932677369238736406007250129466597617814603832211289487312273433454168824443293630243397203521491455204‾x = \frac{163280}{1931} = 84.\overline{55722423614707405489383738995339202485758674262040393578456758156395649922320041429311237700673226307612635939927498705334023821853961677887105126877265665458311755567063697566027964785085447954427757638529259451061626100466079751424132573795960642154324184360435007767995857068876229932677369238736406007250129466597617814603832211289487312273433454168824443293630243397203521491455204}

80x−2000=1045.5x−83640−965.5x=−81640x=1632801931\begin{aligned}80 x - 2000 &= 1045.5 x - 83640\\-965.5 x &= -81640\\x &= \frac{163280}{1931}\end{aligned}

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