Math Problem Solver

\[ 3\frac{1}{4} + 2\frac{2}{3} = \frac{71}{12} = 5.91\overline{6} \]

The sum can be computed by rewriting each term over a common denominator, where the least common denominator of \(\frac{3}{1}\), \(\frac{1}{4}\), \(\frac{2}{1}\), and \(\frac{2}{3}\) is \(12\). \[ \begin{aligned} 3\frac{1}{4} + 2\frac{2}{3} &= \frac{3 \cdot 12}{1 \cdot 12} + \frac{1 \cdot 3}{4 \cdot 3} + \frac{2 \cdot 12}{1 \cdot 12} + \frac{2 \cdot 4}{3 \cdot 4} \\ &= \frac{36 + 3 + 24 + 8}{12} \\ &= \frac{71}{12} \end{aligned} \]