y'''' - 5y''+4y=0

asked by guest
on Nov 18, 2024 at 11:27 pm



You asked:

Solve the equation \(y^{(4)} - 5 \cdot y^{\prime \prime} + 4 y = 0\) for the variable \(y\).

MathBot Answer:

\[y{\left(t \right)} = C_{1} e^{- 2 t} + C_{2} e^{- t} + C_{3} e^{2 t} + C_{4} e^{t}\]

\(C_{1}\), \(C_{2}\), \(C_{3}\), \(C_{4}\) are arbitrary constants.


\(e\) is Euler's number, a mathematical constant that is approximately \(2.71828\).