x"+2x'+x=0

asked by guest
on Oct 21, 2024 at 3:44 am



You asked:

Solve the equation \(x^{\prime \prime} + 2 \cdot x^{\prime} + x = 0\) for the variable \(x\).

MathBot Answer:

\[x{\left(t \right)} = \left(C_{2} t + C_{1}\right) e^{- t}\]

\(C_{1}\), \(C_{2}\) are arbitrary constants.

\(e\) is Euler's number, a mathematical constant that is approximately \(2.71828\).

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