2 $\sqrt{d^2+d^2}$ =40
You asked:
Solve the equation \(2 \cdot \sqrt{{d}^{2} + {d}^{2}} = 40\) for the variable \(d\).
MathBot Answer:
The 2 solutions to the equation are: \[\begin{aligned}d &= - 10 \sqrt{2} \approx -14.142136\\d &= 10 \sqrt{2} \approx 14.142136\end{aligned}\]