3(z+6)≥2z²-5
You asked:
Solve the inequality \( 3 \cdot \left(z + 6\right) \ge 2 {z}^{2} - 5 \) for the variable \(z\).
MathBot Answer:
\[\frac{3}{4} - \frac{\sqrt{193}}{4} \le z\leq\frac{3}{4} + \frac{\sqrt{193}}{4}\]
3(z+6)≥2z²-5
You asked:
MathBot Answer:
\[\frac{3}{4} - \frac{\sqrt{193}}{4} \le z\leq\frac{3}{4} + \frac{\sqrt{193}}{4}\]