(tanθ + cotθ) (cosθ + sinθ)= sec θ + cosθ

(tanθ+cotθ)(cosθ+sinθ)=secθ + cosθ

asked by guest
on Nov 13, 2024 at 1:27 am



You asked:

Solve the system of equations:(tan⁡(θ)+cot⁡(θ))(cos⁡(θ)+sin⁡(θ))=sec⁡(θ)+cos⁡(θ)(tan⁡(θ)+cot⁡(θ))(cos⁡(θ)+sin⁡(θ))=sec⁡(θ)+cos⁡(θ)\begin{aligned}\left(\tan\left( θ \right) + \cot\left( θ \right)\right) \left(\cos\left( θ \right) + \sin\left( θ \right)\right) &= \sec\left( θ \right) + \cos\left( θ \right)\\\left(\tan\left( θ \right) + \cot\left( θ \right)\right) \left(\cos\left( θ \right) + \sin\left( θ \right)\right) &= \sec\left( θ \right) + \cos\left( θ \right)\end{aligned}

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