64^x-121=7-4^x

asked by guest
on Mar 31, 2025 at 2:24 am



You asked:

Solve the equation 64x−121=7−4x{64}^{x} - 121 = 7 - {4}^{x} for the variable xx.

MathBot Answer:

The solution is: x=log⁡(323(576+76771)23−333576+767716)log⁡(2)≈1.1571375x = \frac{\log{\left(\frac{3^{\frac{2}{3}} \sqrt{\left(576 + 7 \sqrt{6771}\right)^{\frac{2}{3}} - \sqrt[3]{3}}}{3 \sqrt[6]{576 + 7 \sqrt{6771}}} \right)}}{\log{\left(2 \right)}} \approx 1.1571375

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