The roots of 1/(x-3)-1/(x+5)=1/6 are:
You asked:
Find the zeros of \(\frac{1}{x - 3} - \frac{1}{x + 5} = \frac{1}{6}\)
MathBot Answer:
The zeros of \(- \frac{1}{x + 5} + \frac{1}{x - 3} = \frac{1}{6}\) are: $$\begin{align*}x &= -9\\x &= 7\end{align*}$$