f(x)=-3-4x-1/2 x^2
find zeros
You asked:
Find the zeros of \(f\left( x \right) = -3 - 4 x - \frac{1}{2} \cdot {x}^{2}\)
MathBot Answer:
The zeros of \(f(x)=- \frac{x^{2}}{2} - 4 x - 3\) are: $$\begin{align*}x &= -4 + \sqrt{10}\\x &= -4 - \sqrt{10} \approx -7.16227766016838\end{align*}$$