f(x)=-3-4x-1/2 x^2

find zeros

asked by guest
on Nov 16, 2024 at 9:51 am



You asked:

Find the zeros of f(x)=−3−4x−12x2f\left( x \right) = -3 - 4 x - \frac{1}{2} {x}^{2}

MathBot Answer:

The zeros of f(x)=−x22−4x−3f(x)=- \frac{x^{2}}{2} - 4 x - 3 are: x=−4+10x=−4−10≈−7.16227766016838\begin{align*}x &= -4 + \sqrt{10}\\x &= -4 - \sqrt{10} \approx -7.16227766016838\end{align*}
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