(n-3)! + (n+2)! + (6-2n)!
You asked:
Evaluate the expression: \(\left( n - 3 \right)! + \left( n + 2 \right)! + \left( 6 - 2 n \right)!\)
MathBot Answer:
\[\left( n - 3 \right)! + \left( n + 2 \right)! + \left( 6 - 2 n \right)! = \left(6 - 2 n\right)! + \left(n - 3\right)! + \left(n + 2\right)!\]