(x ^ { 2 } +2x+8) \div (x+2)

asked by guest
on Mar 26, 2025 at 8:21 pm



You asked:

Evaluate the expression: x2+2x+8x+2\frac{{x}^{2} + 2 x + 8}{x + 2}

MathBot Answer:

Evaluated



x2+2x+8x+2=x2+2x+8x+2\displaystyle \frac{{x}^{2} + 2 x + 8}{x + 2} = \frac{x^{2} + 2 x + 8}{x + 2}

Expanded

x2+2x+8x+2=x2x+2+2xx+2+8x+2\frac{{x}^{2} + 2 x + 8}{x + 2} = \frac{x^{2}}{x + 2} + \frac{2 x}{x + 2} + \frac{8}{x + 2}

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