log3^(x+5) + log3^7=2

asked by guest
on Mar 30, 2025 at 3:04 am



You asked:

Solve the equation log⁡(3x+5)+log⁡(37)=2\log\left( {3}^{x + 5} \right) + \log\left( {3}^{7} \right) = 2 for the variable xx.

MathBot Answer:

The solution is: x=−5+log⁡(e22187)log⁡(3)≈−10.179522x = -5 + \frac{\log{\left(\frac{e^{2}}{2187} \right)}}{\log{\left(3 \right)}} \approx -10.179522

ee is Euler's number, a mathematical constant that is approximately 2.718282.71828.

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