y'-4y/x=x^5e^x

asked by guest
on Nov 25, 2024 at 1:24 pm



You asked:

Investigate the equation: \(y^{\prime} - \frac{4 y}{x} = {x}^{5} {e}^{x}\).

MathBot Answer:

\[y{\left(x \right)} = x^{4} \left(- e^{x} + x e^{x} + C_{1}\right)\]

\(C_{1}\) is an arbitrary constant.


\(e\) is Euler's number, a mathematical constant that is approximately \(2.71828\).