If f(x)= 1 − 7x, g(x)= 2x^2 − 6 and h(x)= 3x − 1 / 4x − 9 find:
1. h(1)
You asked:
Given \( f\left( x \right) = 1 - 7 x \), \( g\left( x \right) = 2 \cdot {x}^{2} - 6 \), \( h\left( x \right) = 3 x - \frac{1}{4 x} - 9 \), evaluate \( 1 \), \( h\left( 1 \right) \).
MathBot Answer:
$$\begin{aligned}h\left( 1 \right)&=- \frac{25}{4}\end{aligned}$$
\(1\) is a constant and does not depend on the given functions.