sin^2A + sin^2B + 2 sinA sinB cos(A+B)= sin^2(A+B)

asked by guest
on Mar 18, 2025 at 9:34 pm



You asked:

Investigate the equation: sin⁡(A)2+sin⁡(B)2+2sin⁡(A)sin⁡(B)cos⁡(A+B)=sin⁡(A+B)2{\sin\left( A \right)}^{2} + {\sin\left( B \right)}^{2} + 2 \sin\left( A \right) \sin\left( B \right) \cos\left( A + B \right) = {\sin\left( A + B \right)}^{2}.
    • Axis Limits
    • min x
    • max x
    • min y
    • max y
  • Update Axis Limits
Close Controls

+ Submit Question