-ab^2 - 3b^2c + 2abc

asked by guest
on Apr 06, 2025 at 6:51 am



You asked:

Evaluate the expression: −(ab2)−3b2c+2abc-\left( a {b}^{2} \right) - 3 {b}^{2} c + 2 a b c

MathBot Answer:

Evaluated



−(ab2)−3b2c+2abc=−b2a+2abc−3b2c\displaystyle -\left( a {b}^{2} \right) - 3 {b}^{2} c + 2 a b c = - b^{2} a + 2 a b c - 3 b^{2} c

Factored

−(ab2)−3b2c+2abc=−b(ab−2ac+3bc)-\left( a {b}^{2} \right) - 3 {b}^{2} c + 2 a b c = - b \left(a b - 2 a c + 3 b c\right)

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