-2(x+5)(x-1)^2(x-3)
asked by guest on Apr 02, 2025 at 6:29 pm
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−(2(x+5)(x−1)2(x−3))=−2(x−3)(x−1)2(x+5)\displaystyle -\left( 2 \left(x + 5\right) {\left( x - 1 \right)}^{2} \left(x - 3\right) \right) = - 2 \left(x - 3\right) \left(x - 1\right)^{2} \left(x + 5\right) −(2(x+5)(x−1)2(x−3))=−2(x−3)(x−1)2(x+5)
−(2(x+5)(x−1)2(x−3))=−2x4+36x2−64x+30-\left( 2 \left(x + 5\right) {\left( x - 1 \right)}^{2} \left(x - 3\right) \right) = - 2 x^{4} + 36 x^{2} - 64 x + 30−(2(x+5)(x−1)2(x−3))=−2x4+36x2−64x+30