differentiate with respect to x (1-x/1+x)^3
asked by guest on Nov 19, 2024 at 3:20 am
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MathBot Answer:
ddx[(1−x1+x)3]=0\frac{d}{d x}\left[{\left( 1 - \frac{x}{1} + x \right)}^{3}\right] = 0dxd[(1−1x+x)3]=0