−49y^6z^4−16x^3y^3z^7
factor completely
You asked:
Factor the expression: \(\displaystyle -\left( 49 \cdot {y}^{6} \cdot {z}^{4} \right) - 16 \cdot {x}^{3} \cdot {y}^{3} \cdot {z}^{7}\)
MathBot Answer:
The polynomial factors into the product: \[-\left( 49 \cdot {y}^{6} \cdot {z}^{4} \right) - 16 \cdot {x}^{3} \cdot {y}^{3} \cdot {z}^{7} = - y^{3} z^{4} \cdot \left(16 x^{3} z^{3} + 49 y^{3}\right)\]
asked 9 days ago
active 9 days ago