4y"+4y'-3y=Sen3x

asked by guest
on Mar 30, 2025 at 9:01 pm



You asked:

Investigate the equation: 4⋅y′′+4⋅y′−3y=sin⁡(3x)4 \cdot y^{\prime \prime} + 4 \cdot y^{\prime} - 3 y = \sin\left( 3 x \right).

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