\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\ldots \ldots \:+\frac{1}{2^n}=\frac{2^n-1}{2^n}
Mathbot Says...
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.
\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\ldots \ldots \:+\frac{1}{2^n}=\frac{2^n-1}{2^n}
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.