7+2.3-9%3

asked by guest
on Sep 23, 2024 at 10:11 am



You asked:

Evaluate the expression: \(7 + 2.3 - 9 \:\%\: 3\)

MathBot Answer:

\[7 + 2.3 - 9 \:\%\: 3 = \frac{93}{10} = 9.3\]


\[\begin{aligned}7 + 2.3 - 9 \:\%\: 3& = 7 + 2 + \frac{3}{10} - \left(9 \:\%\: 3\right)\\& = 7 + 2 + \frac{3}{10} - 0\\& = 7 + 2 + \frac{3}{10} + 0\\& = 9 + \frac{3}{10} + 0\\& = \frac{93}{10} + 0\\& = \frac{93}{10}\end{aligned}\]


The notation \(m \% n\) denotes the remainder of the integer \(m\) divided by the integer \(n\). \(m \% n = r\) means that given integers \(m\) and \(n\), where \(n\) is non-zero, there exist integers \(q\) and \(r\), where \(\lvert r \rvert < \lvert n \rvert\), such that \(m = q n + r\). MathBot adopts the convention that the remainder \(r\) and the divisor \(n\) share the same sign. Alternate notations for \(m \% n\) are \(\operatorname{mod}(m, n)\) and \(m \bmod n\).