d √4(t^2-7) / dt

asked by guest
on Mar 21, 2025 at 12:24 am



You asked:

Evaluate the expression: d4(t2−7)dt\frac{d \sqrt{4} \left({t}^{2} - 7\right)}{d t}

MathBot Answer:

Evaluated



d4(t2−7)dt=2(t2−7)t\displaystyle \frac{d \sqrt{4} \left({t}^{2} - 7\right)}{d t} = \frac{2 \left(t^{2} - 7\right)}{t}

Expanded

d4(t2−7)dt=2t−14t\frac{d \sqrt{4} \left({t}^{2} - 7\right)}{d t} = 2 t - \frac{14}{t}

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