(2y+9)/(y^2−6y+8)

asked by guest
on Nov 24, 2024 at 8:23 pm



You asked:

Evaluate the expression: \(\frac{2 y + 9}{{y}^{2} - 6 y + 8}\)

MathBot Answer:

Evaluated



\(\displaystyle \frac{2 y + 9}{{y}^{2} - 6 y + 8} = \frac{2 y + 9}{y^{2} - 6 y + 8} \)


Expanded

\[\frac{2 y + 9}{{y}^{2} - 6 y + 8} = \frac{2 y}{y^{2} - 6 y + 8} + \frac{9}{y^{2} - 6 y + 8}\]


Factored

\[\frac{2 y + 9}{{y}^{2} - 6 y + 8} = \frac{2 y + 9}{\left(y - 4\right) \left(y - 2\right)}\]