log 1.02x
You asked:
Evaluate the expression: \(\log\left( 1.02 x \right)\)
MathBot Answer:
Evaluated
\(\displaystyle \log\left( 1.02 x \right) = \log{\left(\frac{51 x}{50} \right)} \)
Expanded
\[\log\left( 1.02 x \right) = \log{\left(x \right)} - \log{\left(50 \right)} + \log{\left(51 \right)}\]
Factored
\[\log\left( 1.02 x \right) = \log{\left(x \right)} - \log{\left(50 \right)} + \log{\left(51 \right)}\]