$\frac{2x}{x^2-9}$ / $\frac{x}{x+3}$ / $\frac{2x}{x-3}$ =

asked by guest
on Jan 17, 2025 at 7:06 am



You asked:

Evaluate the expression: \(\frac{\frac{\frac{2 x}{{x}^{2} - 9}}{\frac{x}{x + 3}}}{\frac{2 x}{x - 3}}\)

MathBot Answer:

Evaluated



\(\displaystyle \frac{\frac{\frac{2 x}{{x}^{2} - 9}}{\frac{x}{x + 3}}}{\frac{2 x}{x - 3}} = \frac{\left(x - 3\right) \left(x + 3\right)}{x \left(x^{2} - 9\right)} \)

Expanded

\[\frac{\frac{\frac{2 x}{{x}^{2} - 9}}{\frac{x}{x + 3}}}{\frac{2 x}{x - 3}} = \frac{x}{x^{2} - 9} - \frac{9}{x^{3} - 9 x}\]

Factored

\[\frac{\frac{\frac{2 x}{{x}^{2} - 9}}{\frac{x}{x + 3}}}{\frac{2 x}{x - 3}} = \frac{1}{x}\]

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