find the inverse of the function 3x^2+x+10

asked by guest
on Nov 13, 2024 at 11:44 pm



You asked:

Find the inverse of \(3 \cdot {x}^{2} + x + 10\)

MathBot Answer:

For \(-\infty \lt x \le - \frac{1}{6}\) the inverse is \(- \frac{\sqrt{12 x - 119}}{6} - \frac{1}{6}\)
For \(- \frac{1}{6} \le x \lt \infty\) the inverse is \(\frac{\sqrt{12 x - 119}}{6} - \frac{1}{6}\)

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