(y^2/2p)^2+y^2-16y+46=0

asked by guest
on Mar 30, 2025 at 8:05 am



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Investigate the equation: (y22p)2+y2−16y+46=0{\left( \frac{{y}^{2}}{2 p} \right)}^{2} + {y}^{2} - 16 y + 46 = 0.
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