0.0059(x^2/2-12.5+ln(x/5))=0.25

asked by guest
on Sep 19, 2024 at 9:50 am



You asked:

Solve the equation \(0.0059 \cdot \left(\frac{{x}^{2}}{2} - 12.5 + \ln\left( \frac{x}{5} \right)\right) = 0.25\) for the variable \(x\).