if qd=60-15p+p^2 then find out dq/dp
asked by guest on Nov 15, 2024 at 5:09 am
MathBot Answer:
dq=p2−15p+60q=p2−15p+60d\begin{aligned}d q &= p^{2} - 15 p + 60\\q &= \frac{p^{2} - 15 p + 60}{d}\end{aligned}dqq=p2−15p+60=dp2−15p+60ddp[p2−15p+60d]=2p−15d\frac{d}{d p} \left[\frac{p^{2} - 15 p + 60}{d}\right]=\frac{2 p - 15}{d}dpd[dp2−15p+60]=d2p−15
