(h+ p)(h+ p)(h+ p)(h+ p)
asked by guest on Mar 15, 2025 at 12:55 pm
You asked:
MathBot Answer:
(h+p)(h+p)(h+p)(h+p)=(h+p)4\displaystyle \left(h + p\right) \left(h + p\right) \left(h + p\right) \left(h + p\right) = \left(h + p\right)^{4} (h+p)(h+p)(h+p)(h+p)=(h+p)4
(h+p)(h+p)(h+p)(h+p)=h4+4h3p+6h2p2+4p3h+p4\left(h + p\right) \left(h + p\right) \left(h + p\right) \left(h + p\right) = h^{4} + 4 h^{3} p + 6 h^{2} p^{2} + 4 p^{3} h + p^{4}(h+p)(h+p)(h+p)(h+p)=h4+4h3p+6h2p2+4p3h+p4