⅔√27−5√12+√3=

asked by guest
on Nov 18, 2024 at 7:50 am



You asked:

Evaluate the expression: 2327−512+3\frac{2}{3} \sqrt{27} - 5 \sqrt{12} + \sqrt{3}

MathBot Answer:

2327−512+3=−73≈−12.12435565298214105469212439054111\frac{2}{3} \sqrt{27} - 5 \sqrt{12} + \sqrt{3} = - 7 \sqrt{3} \approx -12.12435565298214105469212439054111

2327−512+3=23⋅27−5⋅12+3=23⋅3⋅3−5⋅12+3=2⋅3−5⋅12+3=2⋅3−5⋅2⋅3+3=2⋅3−10⋅3+3=−8⋅3+3=−7⋅3\begin{aligned}\frac{2}{3} \sqrt{27} - 5 \sqrt{12} + \sqrt{3}&=\frac{2}{3} \cdot \sqrt{27} - 5 \cdot \sqrt{12} + \sqrt{3}\\&=\frac{2}{3} \cdot 3 \cdot \sqrt{3} - 5 \cdot \sqrt{12} + \sqrt{3}\\&=2 \cdot \sqrt{3} - 5 \cdot \sqrt{12} + \sqrt{3}\\&=2 \cdot \sqrt{3} - 5 \cdot 2 \cdot \sqrt{3} + \sqrt{3}\\&=2 \cdot \sqrt{3} - 10 \cdot \sqrt{3} + \sqrt{3}\\&=-8 \cdot \sqrt{3} + \sqrt{3}\\&=-7 \cdot \sqrt{3}\end{aligned}

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