x²-4+3x
asked by guest on Mar 17, 2025 at 5:34 am
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MathBot Answer:
x2−4+3x=x2+3x−4\displaystyle {x}^{2} - 4 + 3 x = x^{2} + 3 x - 4 x2−4+3x=x2+3x−4
x2−4+3x=(x−1)(x+4){x}^{2} - 4 + 3 x = \left(x - 1\right) \left(x + 4\right)x2−4+3x=(x−1)(x+4)